In 1930, a person’s age was 8 times that of his shown. In 1938, the father's age became ten times that of his son’s age in 1930.
In 1930, a person’s age was 8 times that of his shown. In 1938, the father's age became ten times that of his son’s age in 1930. The ages of the son and father in 1940 were respectively
(a) 16 years, 58 years (b) 15 years, 50 years (c) 14 years, 42 years (d) 13 years, 34 years
14 views
1 Answers
(c) Let son’s age in 1930 be x years
then father’s age in 1930 will be 8x years
In 1938, father’s age= (8x + 8) years
As per the question, 8x + 8 = 10x
∴ 2x = 8
or x = 4 years
Hence son’s age in 1930 = 4 years
Father’s age in 1930 = 8(4) = 32
Therefore, the age of son and father in 1940 will be 14
years and 42 years respectively
14 views
Answered