The decomposition of A into product has value of K as 4.5 x 103 sec-1 at 10º C and energy of activation 60 kJ/mol. At what temperature would K be
1.5 x 104 sec-1.
Solution:
Explanation: Use one of the Pythagorean identity namely,
sec2A=1+tan2A
LHS = sec4A−sec2A
=(sec2A)2−sec2A
=(1+tan2A)2−(1+tan2A)
=1+2tan2A+tan4A−1−tan2A
=tan4A+tan2A
= RHS
(a) Kc=[PCl3] [Cl2] / [PCl5]
(b) 120.48
(c) (i) equilibrium will shift on RHS.
(ii) equilibrium will shift on LHS.
(iii) equilibrium will shift on RHS.
