A tuning fork of unknown frequency gives 4 beats/sec with a tuning fork of frequency 310Hz.It gives the same no. of beats/sec on filing.find the unknown frequency.
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A tuning fork of unknown frequency gives 4beats/sec with a tuning fork of freq. 310Hz.It gives the same no. of beats/sec on filing.find unknown freq.
Its not timing its tuning
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When temperature increases, the frequency of a tuning fork.
(b) : When temperature increases, l increases Hence frequency decreases.
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A tuning fork of frequency 480 Hz is used to vibrate a sonometer wire having natural frequency 240 Hz.
The correct answer is (b) 480 Hz EXPLANATION: The simple harmonic disturbance produced by the tuning fork is transmitted to the wire through the bridges in the sonometer. Hence the wire will...
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A tuning fork of frequency 480 Hz is used to vibrate a sonometer wire having natural frequency 410 Hz.
The correct answer is (b) 480 Hz EXPLANATION: The sonometer wire will vibrate with the same frequency as the tuning fork.
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A sonometer wire of length l vibrates in fundamental mode when excited by a tuning fork of frequency 416 Hz.
(a) vibrate with a frequency of 416 Hz EXPLANATION: The sonometer wire will vibrate with the same frequency as the tuning fork.
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A sonometer wire supports a 4 kg load and vibrates in fundamental mode with a tuning fork of frequency 416 Hz.
The correct answer is (d) 16 kg. EXPLANATION: Since the wire is made to vibrate with the same tuning fork the frequency of vibration remains the same. Equating the frequencies in both the...
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A tuning fork sends sound waves in air. If the temperature of the air increases, which of the following parameters will change ?
(c) Wavelength . EXPLANATION: When the sound wave is being sent by a tuning fork, its displacement amplitude, frequency and the time period will remain the same even if the temperature changes....
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A tuning fork of frequency 512 Hz is vibrated with a sonometer wire and 6 beats per second are heard.
The correct answer is (a) 506 Hz EXPLANATION: The frequency of beats ν = |ν₁-ν₂| = 6 Hz where ν₁ = 512 Hz, ν₂ = frequency of sonometer. Thus ν₂ is either...
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An electrically maintained tuning fork vibrates with constant frequency and constant amplitude.
(a) larger wavelength (c) larger velocity EXPLANATION: The velocity of sound V is directly proportional to the square root of the temperature. So if the temperature increases the velocity of the sound also...
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When two tuning forks (fork 1 and fork 2) are sounded simultaneously, 4 beats per second are heard. Now,
The correct answer is (3) |f1−f2| =4 Since mass of second tuning fork increases so f2 decrease and beats increase so f1>f2 ⇒ f2=f1−4 = 196
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