How to prove sec^4A-sec^2A=tan^4A+tan^2A

if  3cotA= 4 check whether 1-tan2A/1+tan2A =  cos2A – sin2A or not. Ans:  [note:You can solve it without using value] RHS = cos2A – sin2A [using  formula sin2A + cos2A = 1 hence cos2A...

Solution: tan (A + B) = √3 ⇒ tan (A + B) = tan 60° ⇒ (A + B) = 60° ... (i)  tan (A – B) = 1/√3 ⇒ tan (A - B) =...

Answer: We have tan A = cot B ⇒ tan A = tan (90° - B) ⇒ A = 90° - B ⇒ A + B = 90°

Solution: We know that sec2x-tan2x = 1 sec2x = 1+tan2x sec2x = 1 + {x - (1/4x)}2 sec2x = 1 + x2 + 1/16x2 - 2*x*1/4x sec2x = 1 + x2 + 1/16x2 - 1/2 sec2x = (x+1/4x)2 sec x = +- (x+1/4x) So, sec x -...

I don't understand the 4 th

tan 35° = tan (90° - 55°) = cot 55° tan 40° = tan (90° - 50°) = cot 50° Cot 55 tan 55∙ cot 50 tan 50 =1 ∙ 1   = 1

cosec (65 + θ ) = sec (90 – (65 + θ )) = sec (25 – θ ) tan (55 – θ ) = cot (90 – (55 – θ ) = cot (35 +...

tan 7° tan 23° tan 60° tan (90° - 23) tan (90° - 7°) ⇒ tan 7° tan 23° tan 60° cot 23° tan 60° 1 ∙ 1 ∙ √3 = √3

Its not timing its tuning