There are two cans, out of which one can contains 30% diesel and the rest is kerosene and the other can contains 20% diesel and the rest is kerosene. Find the difference between the amounts of kerosene that should be mixed from containers to get 35 litres of total mixture so that the ratio of diesel to kerosene is 2 : 5.?

35 litres
25 litres
22 litres
30 litres

LohaHridoy

10 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 2 : 25 litres

Let the cost of 1 litre kerosene be Rs.100

Kerosene in 1 litre mix in 1^st can = 7/10

Cost price of 1 litre kerosene in 1^st can = 70

Kerosene in 1 litre mix in 2^nd can = 8/10

Cost price of 1 litre kerosene in 2^nd can = 80

Kerosene in 1 litre of mixture = 5/7 litres

Mean price of mixture = 500/7

By rule of Alligation,

Ratio of kerosene mixed from containers

= (500/7 – 70) : (80 – 500/7) = 1 : 6

Total mixture = 35 litres

Required difference in amount = 35 × 6/7 – 35 × 1/7 = 25 litres

10 views Answered 2022-09-04 04:29

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