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Option 5 : 60 kmph

Given,

Total distance between the A and B = 540 × 4/3 = 720 km

Remaining distance = 720 - 540 = 180 km

Let initial speed of train be M kmph.

Increased speed of the train = M + 15

Then,

⇒ 180/M - 180/(M + 15) = 1

⇒ 180M + 2700 - 180M = M2 + 15M

⇒ M2 + 15M - 2700 = 0

Solving,

⇒ M = 45, M = -60

Increased speed of the train = 45 + 15 = 60 kmph
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