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Option 5 : 60 kmph
Given,
Total distance between the A and B = 540 × 4/3 = 720 km
Remaining distance = 720 - 540 = 180 km
Let initial speed of train be M kmph.
Increased speed of the train = M + 15
Then,
⇒ 180/M - 180/(M + 15) = 1
⇒ 180M + 2700 - 180M = M2 + 15M
⇒ M2 + 15M - 2700 = 0
Solving,
⇒ M = 45, M = -60
Increased speed of the train = 45 + 15 = 60 kmph
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