1 Answers

Option 1 : 1 and 2 only

For a transmission line of capacitance is considered, then-current drawn by the line is some of the load current & capacitive current. Most of the load current is inductive, so it will be lagging.

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The phasor diagram for the above circuit diagram would be,

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Hence IS automatically becomes less than IR i.e. IS < IR

If no capacitance is considered for the line, then sending end current and Receiving end current will be equal, i.e. IS = IR, which means sending end current is increased.

If sending end current is an increase, then automatically sending end power is increased.

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