1 Answers
Option 1 : Quantity A > Quantity B
Quantity A:
Suppose ‘s’km/hr is the speed of the car and ‘D’ km is the distance;
If he increases his speed by 8 km/hr, he takes 2 hours less time;
∴ D/s – D/(s + 8) = 2
⇒ D = /8 ----(1)
If he drives 8 km/hr slower, he takes 4 hours more time;
∴ D/(s – 8) – D/s = 4
⇒ D = /8 ----(2)
From equation (1) and (2);
/8 = /8
⇒ 2s + 16 = 4s – 32
⇒ 2s = 48
⇒ s = 24
∴ D = /8 = 192 km
Quantity B:
Suppose ‘s’ km/hr is the speed of the car and ‘D’ km is the distance;
If he increases his speed by 10 km/hr, he takes 1 hour less time;
∴ D/s – D/(s + 10) = 1
⇒ D = /10 ----(1)
If he further increases his speed by 5 km/hr, he takes further 20 minutes ( = 1/3 hours) lesser time;
∴ D/s – D/(s + 15) = (1 + 1/3)
⇒ D = /15 ----(2)
From equation (1) and (2);
/10 = /15
⇒ 9(s + 10) = 8(s + 15)
⇒ 9s + 90 = 8s + 120
⇒ s = 30
∴ D = /10 = 120 km
∴ Quantity A > Quantity B