Study the given pie-chart and answer the question that follows. The pie-chart represents the percentage distribution of candidates qualified in a bank examination from six different districts of a State in 2016. The total number of qualified candidates from the State is 68000. What is the difference (to the nearest whole number) between the average number of qualified students from Districts A, C, and F and the average number of qualified students from Districts B, D, and E?

Option 2 : 907

Calculation:

Total percentage of qualified students from the Districts A, C and F = (15% + 28% + 5%)

⇒ 48%

The average number of qualified students from the Districts A, C and F = (48% of 68000)/3

⇒ (48/100 × 68000)/3

⇒ 32640/3

⇒ 10880

Total percentage of qualified students from the Districts B, D and E = (25% + 18% + 9%)

⇒ 52%

The average number of qualified students from the Districts B, D and E = (52% of 68000)/3

⇒ (52/100 × 68000)/3

⇒ 35360/3

⇒ 11786.66 ~ 11787

Required difference = (11787 – 10880)

⇒ 907

∴ The required difference is 907