There are two vessels containing milk and water in the ratio 3 ∶ 2 and 5 ∶ 4, in what ratio must the contents of these vessels be mixed such that the resultant vessels contains milk and water in the ratio 7 ∶ 5?

There are two vessels containing milk and water in the ratio 3 ∶ 2 and 5 ∶ 4, in what ratio must the contents of these vessels be mixed such that the resultant vessels contains milk and water in the ratio 7 ∶ 5? Correct Answer 5 : 3

Given:

Two vessels contain milk and water in the ratio 3 ∶ 2 and 5 ∶ 4.

Concept:

Basic mixture concept.

Calculation:

Fraction of milk in 1st mixture = 3/5

Fraction of milk in 2nd mixture = 5/9

Using allegation method:

Hence,

Required ratio = (21 – 20)/36 ∶ (36 – 35)/60

⇒ 1/36 ∶ 1/60

⇒ 5 ∶ 3

∴ The required ratio is 5 ∶ 3.

Related Questions

Jar A comprises a mixture of milk and water in the ratio of 3 : 2 respectively. Another mixture of milk and water is added to jar A and the ratio of milk and water in the resultant mixture changes. What was the initial quantity of mixture present in Jar A? I. The ratio of milk and water in the mixture that was added to Jar A was 2 : 1 respectively. II. The ratio of the new quantities of milk and water in Jar A was 8 : 5 respectively. The quantity of water in the mixture added to jar A was 6 litre.