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A bag contains 4 red balls, 6 blue balls and 8 pink balls. One ball is drawn at random and replace with 3 pink balls. A second ball was drawn without replacement. What is the probability that the first ball drawn was either red or blue in colour and the second ball drawn was pink in colour? 

A bag contains 4 red balls, 6 blue balls and 8 pink balls. One ball is drawn at random and replace with 3 pink balls. A second ball was drawn without replacement. What is the probability that the first ball drawn was either red or blue in colour and the second ball drawn was pink in colour?  Correct Answer None of these

Case 1:

Probability of getting first ball either red or blue in colour

(4C1 × 6C0 + 6C1 × 4C0)/18C1

⇒ (4 + 6)/18

⇒ 10/18

Now,

3 more pinks balls are added without replacement

Total number of balls = 20

Probability of getting 1 pink ball

⇒ 11C1/20C1

⇒ 11/20

∴ Required probability = 10/18 × 11/20 = 11/36

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