A bag contains 8 red balls and 12 blue balls. One ball Is drawn at random and replaced with 5 green balls. A second ball is drawn without replacement. What Is the probability that the first ball drawn is red in colour and the second ball drawn is blue in colour?

A bag contains 8 red balls and 12 blue balls. One ball Is drawn at random and replaced with 5 green balls. A second ball is drawn without replacement. What Is the probability that the first ball drawn is red in colour and the second ball drawn is blue in colour? Correct Answer 1/5

Given:

A bag contains 8 red balls and 12 blue balls

One ball Is drawn at random and replaced with 5 green balls. A second ball was drawn without replacement.

Calculation:

Probability of getting 1st ball as red = 8/(8 + 12) = 8/20

Probability of getting 2nd ball as blue = 12/(8 + 12 + 5 – 1) = 12/24

∴ Required probability = 8/20 × 12/24 = 1/5

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