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Ratio between speed of boat P and Q in still water is 8∶6 and speed of current is 8 km/hr. Boat Q starts from A in the downstream,2 hours earlier than Boat P and it is found that Boat P is 32 km ahead of boat Q after 16 hours of its start. If boat P starts from point B in down steam at the same time and distance between A and B is 216 km, then find at what time boat P and Q meet each other.

Ratio between speed of boat P and Q in still water is 8∶6 and speed of current is 8 km/hr. Boat Q starts from A in the downstream,2 hours earlier than Boat P and it is found that Boat P is 32 km ahead of boat Q after 16 hours of its start. If boat P starts from point B in down steam at the same time and distance between A and B is 216 km, then find at what time boat P and Q meet each other. Correct Answer 12/5 hr

Given:

Ratio between speed of boat P and Q in still water = 8 ∶ 6

Speed of current = 8 km/hr

Distance between A and B = 216 km

Calculations:

Let speed of boat P and Q in still water be = 8x km/hr and 6x km/hr

Downstream speed of boat P = (8x + 8) km/hr

Down steam speed of boat Q = (6x + 8) km/hr

 According to question

⇒ 16(8x + 8) – 32 = 2(6x + 8) + 16(6x + 8)

⇒ 128x + 128 – 32 = 12x + 16 + 96x + 128

⇒ 20x = 48

⇒ x = 48/20 = 12/5 hours

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