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The distance between two points X and Y is 480 km. Train A starts from X and train B starts from Y and meet at the point W, which is 180 km away from X. If, Train A starts two hour earlier than train B, then in what time (in hour) train B reaches point W? (Assume speeds of X and Y are same )

The distance between two points X and Y is 480 km. Train A starts from X and train B starts from Y and meet at the point W, which is 180 km away from X. If, Train A starts two hour earlier than train B, then in what time (in hour) train B reaches point W? (Assume speeds of X and Y are same ) Correct Answer 3 hours

Given:

Distance between X and Y points = 480 km

Starting time of train A = 2 hours before train B 

Speed of Train A = Speed of Train B

Meeting point of both trains = 180 km from point X

Concept used:

If train A starts 2 hours before than train B, it means Train A travels for 2 more hours than train B

Calculation:

Let the time taken by train B be t hours

So, time taken by train A = (t + 2) hours

Now, distance covered by train A in (t + 2) hours = (480 - 180) km

⇒ 300 km

Now, if their speed is same, So,

300/(t + 2) = 180/t

⇒ 300t = 180t + 360

⇒ 120t = 360

⇒ t = 3 hours

∴ Time taken by train B is 3 hours

 

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