There are three gyms A, B and C. Each of them have men and women. The number of men in A is the average of the men in B and C. The average number of women in A and C is equal to the number of women in B. The number of women in B is 60 and Men in A and B are 72 and 36 respectively. What is the average number of members in A, B and C?

There are three gyms A, B and C. Each of them have men and women. The number of men in A is the average of the men in B and C. The average number of women in A and C is equal to the number of women in B. The number of women in B is 60 and Men in A and B are 72 and 36 respectively. What is the average number of members in A, B and C? Correct Answer 132

Given:

The number of women in B = 60

Men in A and B = 72 and 36 respectively

Formula:

Average of n numbers a1, a2, ..., an = (a1 + a2 + ... + an) / n

Calculation:

Men(A) = / 2

2 × 72 = 36 + men(C)

Men(C) = 108

/ 2 = 60

Women(A) + Women(C) = 120

Women(B) = 60

The average number of members in A, B and C = / 3 = (72 + 108 + 36 + 120 + 60) / 3 = 132

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