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What is the population of district X? I. The number of males in district X is M and the number of females in district X is F. 32 times of F is equal to 33 times of M. The difference between female and male in district X is 50,000. II. The population of district X is 65/87 of that of district Y. The total population in district X and district Y together is 7,600,000.

What is the population of district X? I. The number of males in district X is M and the number of females in district X is F. 32 times of F is equal to 33 times of M. The difference between female and male in district X is 50,000. II. The population of district X is 65/87 of that of district Y. The total population in district X and district Y together is 7,600,000. Correct Answer The data either in statement I alone or in statement II alone are sufficient to answer the question.

Calculation:

From statement I:

Given, 32F = 33M

⇒ F/M = 33/32

⇒ F : M = 33 : 32

Also, F – M = 50,000      

∴ (33 – 32) units = 50000

⇒ 1 unit = 50000

∴ (33 + 32) units = 65 × 50000

⇒ 65 units = 65 × 5000 = 32,50,000

∴ Total population of district X = 32,50,000

For statement II:

III. The population of district X is 65/87 of that of district Y. The total population in district X and district Y together is 76,00000.

Given, X = 65/87 of Y

⇒ X/Y = 65/87

⇒ X : Y = 65 : 87

Also given, (X + Y) = 76,00000

⇒ (65 + 87) units = 76,00000

⇒ 152 units = 76,00000

⇒ 1 unit = 50,000

⇒ 65 units = 32,50,000

∴ Total population of district X = 32,50,000

∴ The data either in statement I alone or in statement II alone are sufficient to answer the question.

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