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Eight years ago, Poorvi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ration between the ages of her daughter and her son that time will be 7 : 6. If Poorvi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter?

Eight years ago, Poorvi’s age was equal to the sum of the present ages of her one son and one daughter. Five years hence, the respective ration between the ages of her daughter and her son that time will be 7 : 6. If Poorvi’s husband is 7 years elder to her and his present age is three times the present age of their son, what is the present age of the daughter? Correct Answer 23 years

Given:

Poorvi’s age = Sum of present age of her one son and one daughter.

Ratio of age of her daughter and son after 5 years = 7 : 6.

Poorvi’s husband is 7 years elder to her

Poorvi’s husband is 3 times the present age of their son.

Calculation:

Let present age of her son = x.

Present age of Poorvi’s husband = 3x

Present age of poorvi = 3x – 7

Eight years ago, Poorvi’s age = 3x – 15

Present age of her daughter = (3x – 15) – x = (2x – 15)

After 5 years, age of her daughter = (2x – 10)

Age of her son = ( x + 5)

⇒ (2x – 10) : (x + 5) = 7 : 6

⇒ 12x – 60 = 7x + 35

⇒ 5x = 95

⇒ x = 19

∴ present age of her daughter = (2x – 15) = 23 years.

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