A roller is 70 cm long and has a diameter of 2 cm. It takes exactly 100 rotations of the roller to level a road. If the cost of using the roller is 0.5 rupees per square cm, then what is the cost of levelling the road?

A roller is 70 cm long and has a diameter of 2 cm. It takes exactly 100 rotations of the roller to level a road. If the cost of using the roller is 0.5 rupees per square cm, then what is the cost of levelling the road? Correct Answer 22000

Given:

The length of the roller is 70 cm

The diameter of the roller is 2 cm

Concept:

The curved surface area of the roller = 2 × π × r × h

Calculation:

⇒ Radius of the roller = 2/2 = 1 cm

⇒ Length of the roller = 70 cm

⇒ The curved surface area of the roller = 2 × (22/7) × (1) × (70) = 440 cm2

⇒ In one rotation the roller covers 440 cm2. In 100 rotations, the roller covers = 440 × 100 = 44000 cm2

⇒ Cost of levelling = 44000 × 0.5 = 22000 rupees

∴ The required result will be 22000.

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