Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels onwards A at a speed of 25 kmph. At what time will they meet?

Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels onwards A at a speed of 25 kmph. At what time will they meet? Correct Answer 10 a.m.

Given:

Distance between the two stations = 110 km

Train from station A starts at 7 a.m

Train from station  B starts at 8 a.m

Speed of Train from A = 20kmph

Speed of Train from B = 25kmph

Formula Used:

Distance = speed × Time 

Calculation:

Let us assume that two trains meet x hours after 7.am

Distance travelled by train from A = 20x km

Distance travelled by train from B = 25(x - 1) km

According to question,

⇒ 20x + 25(x -1) = 110

⇒ 45x = 135

⇒ x = 3 hour

They will meet at 3 hours after 7 a.m

∴ They will meet at 10 a.m

Related Questions

The question below is followed by two statements I and II. You have to determine whether the data given is sufficient for answering the question. You should use the data and your knowledge of mathematics to choose the best possible answer. Train A departs at 9 : 20 am and train B departs at 10 : 50 am and they travel towards each other. After how much amount of time will the trains meet? I) Train A travels with a speed of 10 kmph and the difference between the speed of two trains is 6 kmph and both the trains are 160 km apart. II) Train B travels at a speed greater than Train A which travels with 10 kmph by 6kmph separated by a distance of 160 km.