Bissoy.com
Doctors Medicines MCQs Q&A

If Mean is M, Median is Md, Mode is Mo, what is the relation between Mean, Median and Mode? 

If Mean is M, Median is Md, Mode is Mo, what is the relation between Mean, Median and Mode?  Correct Answer Mo = 3Md - 2M

Given:

Mean = M

Mode = Mo

Median = Md

Calculation:

The relation between Mean(M), median(Md), and Mode(Mo)

⇒ Mo = 3Md – 2M

∴ The relation between Mean, Median, and Mode is Mo = 3Md – 2M

Important PointsMean = Total sum of all values in the sample divided by the number of observations and it is denoted by x̅ Results.

x̅  = ∑fi/n and I = 1, 2, 3, ..........

Median = Median of a distribution locates a central point which divides the distribution into two equal halves

Median = (n + 1)/2

Mode = Mode is the value of the distribution that occurs more frequently.

Related Questions

Which of the following are the correct statements with regard to positive skewed distribution? (A) Mean > Media > Mode (B) Mean < Median < Mode (C) Q3 - Median < Median - Q1 (D) Q3 - Median > Median - Q1 (E) Mean = Median = Mod Choose the correct answer from the options given below:
Consider the statements given below- A: Relationship between Mean, Median and Mode is : Mode = 3 Median – 2 Mean B: It is also possible that there can be more than one mode or no mode for a data set. C: In a data set, half of the data points are smaller than the median and half of the data points are larger. Which of the above statement(s) is/are TRUE?
Which two of the following statements are true?  a) Skewness studies the flatness or peakedness of the distribution  b) A positively skewed distribution curve is stretched more to the right than to the left  c) On the basis of empirical relationship between mean, mode and median for moderately asymmetrical distribution, Karl Pearson's coefficient of skewness can be measured by 3 (Mean -Median) divided by Standard Deviation  d) If mean < mode, the distribution is positively skewed  Choose the correct option from those below: 
The maximum weight lifted by 750 participants are recorded and it is found that the Mean and the Median of this distribution are both more than the Mode. If the Mean and the Median are 184 Kg and 178 Kg respectively, then which of the following is the most likely value of the Mode (in kg).
According to Naiya̅yikas we ascertain the relation of universal concomitance between x and y :  (A) We can determine the relation only if we can determine the relation of essential identity between x and y   (B) By perceiving that in all cases the presence of x is accompanied by the presence of y  (C) We can determine the relation only if we can determine the relation of cause and effect between x and y  (D) By not perceiving any instance where the presence of x is not accompanied by the presence of y or vice-versa.  Choose the correct answer from the options given below : 
What is the formula for the median of Grouped data? * h b) Median = L + * h c) Median = L + + h d) Median = L * * h
hat will be the output of the following R code?
> centre <- function(x, type) {+ switch(type,+ mean = mean(x),+ median = median(x),+ trimmed = mean(x, trim = .1))+ }> x <- rcauchy(10)> centre(x, "mean")
If the difference between the mode and median is 2, then the difference between the median and mean is:
Mean of an observation is 2 times of mode. If median is 5, what is the average of mode and median of the observation?
The mean and median of observation 1 are 21 & 22 respectively. The mean of observation 2 whose median is 21 & mode is the same as observation 1.