On using anti bacterial drug it has been observed that (i) The number of bacteria decreases by 4% in the first hour. (II) The number increases by 5% in the second hour. The number has increased by 10% in the third hour. (iii) If the number of bacteria is 500,000, then what is the % increase in the number of bacteria at the end of 3 hours.
On using anti bacterial drug it has been observed that (i) The number of bacteria decreases by 4% in the first hour. (II) The number increases by 5% in the second hour. The number has increased by 10% in the third hour. (iii) If the number of bacteria is 500,000, then what is the % increase in the number of bacteria at the end of 3 hours. Correct Answer 10.88%
Given:
The number of bacteria decreases in first hour = 4%
The number of bacteria increases in second hour = 5%
The number of bacteria increases in third hour = 10%
Total number of bacteria = 500,000
Time = 3 hours
Calculation:
According to the question
⇒ (500,000 × 96/100 × 105/100 × 110/100)
⇒ (500,000 × 24/25 × 21/20 × 11/10)
⇒ 554,400
Now,
⇒ (554,400 – 500,000)
⇒ 54,400
Required percentage = (54,400/500,000 × 100)
⇒ (272/25)%
⇒ 10.88%
∴ Required percentage increase is 10.88%