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Given below are quantities named A,B and C. Based on the given information, you have to determine the relation between the quantities. You should use the given data and your knowledge of mathematics to choose among the possible answer. Quantity A: Tap1 and Tap2 can fill the tank in 16 hours and 25 hours respectively. Both the taps opened together. After some time Tap 1 is closed and after that the tank is filled in 12 hours. In how many hour Tap 1 and 2 work together? Quantity B: Three taps 1, 2, 3 can fill a cistern in 10,14,18 hours respectively. If tap 1 is kept open all the time and tap 2 and 3 is opened alternatively for an hour then find in how many hours the tank will be filled? Quantity C: Two taps 1 and 2 are such that tap 1 fills the tank in 10 hours and tap2 empties it in 20 hours. If tap 1 is opened first and after 5 hours tap 1 is closed and tap 2 is opened, then the tank emptied in x hours and find the value of x?

Given below are quantities named A,B and C. Based on the given information, you have to determine the relation between the quantities. You should use the given data and your knowledge of mathematics to choose among the possible answer. Quantity A: Tap1 and Tap2 can fill the tank in 16 hours and 25 hours respectively. Both the taps opened together. After some time Tap 1 is closed and after that the tank is filled in 12 hours. In how many hour Tap 1 and 2 work together? Quantity B: Three taps 1, 2, 3 can fill a cistern in 10,14,18 hours respectively. If tap 1 is kept open all the time and tap 2 and 3 is opened alternatively for an hour then find in how many hours the tank will be filled? Quantity C: Two taps 1 and 2 are such that tap 1 fills the tank in 10 hours and tap2 empties it in 20 hours. If tap 1 is opened first and after 5 hours tap 1 is closed and tap 2 is opened, then the tank emptied in x hours and find the value of x? Correct Answer <,<

Quantity A,

tap 1 + tap 2 = 1/16 + 1/25 = 41/400

Tap 2 filled alone in 12 hours = 12/25

Remaining = 13/25

Required time = (13/25) × (400/41) = 5.07 hours

Quantity B,

Total units of work = 90

1’s one hour work = 9

2’s one hour work = 6

3’s one hour work = 5

Work done by three taps in 2 hours = 15 + 14 = 29 units

Work done in 6 hours = 29 × 3 = 87 units

Remaining will be done by tap 1 and tap 2 = 3/15 = 1/5 hours

Total time required = 6(1/5) hours = 6.2 hours

Quantity C,

Tap 1 = 1/10

Tap 2 = 1/20

LCM of (10,20) = 20 units

Tap 1 fill the tank in one hour = 2 units

Tap 2 emptied the tank in one hour = 1 unit

Tap 1 opened for 5 hours = 2 × 5 = 10 units of tank filled

Tap 2 can empty in = 10 /1 = 10 hours

Tank emptied in x = 10 hours

Quantity A < Quantity B < Quantity C

Related Questions

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