Pipe A and Pipe B can together fill a tank in 4 hours. But, if pipe A was stopped for some time and then restarted, it took 6 hours to fill the tank. If pipe A is twice as efficient as pipe B, then for how much time was pipe A stopped?
Pipe A and Pipe B can together fill a tank in 4 hours. But, if pipe A was stopped for some time and then restarted, it took 6 hours to fill the tank. If pipe A is twice as efficient as pipe B, then for how much time was pipe A stopped? Correct Answer 3 hours
Let pipe B take ‘x’ hours to fill the tank alone
Part filled by pipe B in 1 hr. = 1/x
∵ Pipe A is twice as efficient as B, part filled by pipe A in 1 hr. = 2/x
Part filled by pipes A & B in 1 hr. = 1/x + 2/x = 3/x
But, together they can fill the tank in 4 hours,
⇒ 3/x = 1/4
⇒ x = 12
Part filled by A in 1 hr. = 2/x = 2/12 = 1/6
Part filled by B in 1 hr. = 1/12
Now, let pipe A be stopped for ‘t’ hours, then, work done in 6 hours is,
⇒ (6 – t) × 1/6 + 6 × 1/12 = 1
⇒ 1 – t/6 + 1/2 = 1
⇒ t/6 = 1/2
⇒ t = 6/2 = 3 hours
∴ Pipe A was stopped for 3 hours