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Pipes A and B are used to fill the tank. A can fill the tank twice as fast as B. Pipe C and D can empty the tank. D takes same time to empty the tank as taken by B to fill it. Pipe C can empty tank in 6 hours. If all 4 are opened together, how much hour would it take to fill the tank? (Assume: D can empty tank twice as fast as C.)

Pipes A and B are used to fill the tank. A can fill the tank twice as fast as B. Pipe C and D can empty the tank. D takes same time to empty the tank as taken by B to fill it. Pipe C can empty tank in 6 hours. If all 4 are opened together, how much hour would it take to fill the tank? (Assume: D can empty tank twice as fast as C.) Correct Answer 2 hours

Pipe C can empty 1/6 of the tank in an hour

⇒ D can empty 1/3 of tank in an hour (∵ D work twice as fast as C)

⇒ B can fill 1/3 of tank in an hour (∵ D work as fast as B)

⇒ A can fill 2/3 of tank in an hour

⇒ In one hour, part of tank filled = 2/3 – 1/6 = 1/2

∴ Entire tank gets filled in 2 hours.

Related Questions

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