In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: In how many ways can the word ‘DISTURBANCE’ be arranged such that all the consonants are always together? Quantity B: In how many ways can the word ‘DISTURBANCE’ be arranged such that all the vowels are always together?

In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: In how many ways can the word ‘DISTURBANCE’ be arranged such that all the consonants are always together? Quantity B: In how many ways can the word ‘DISTURBANCE’ be arranged such that all the vowels are always together? Correct Answer Quantity A < Quantity B

Solving for Quantity A:

The word ‘DISTURBANCE’ contains 11 different letters, comprising of 7 consonants and 4 vowels

When the consonants are always together, they are considered as one letter

Hence, the 5 letters to be arranged are (DSTRBNC) IUAE

No. of ways of arranging them = 5! = 120 ways

The 7 consonants can be arranged in = 7! = 5040 ways

Hence, required no. of ways = 120 × 5040 = 60480

⇒ Quantity A = 60480

Solving for Quantity B:

The word ‘DISTURBANCE’ contains 11 different letters, comprising of 7 consonants and 4 vowels

When the vowels are always together, they are considered as one letter

Hence, the 8 letters to be arranged are DSTRBNC (IUAE)

No. of ways of arranging them = 8! = 40320 ways

The 4 vowels can be arranged in = 4! = 24 ways

Hence, required no. of ways = 24 × 40320 = 967680

⇒ Quantity B = 967680

∴ Quantity A < Quantity B

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