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A and B can complete a task in 1.5 days. However, A had to leave a few days before the task was completed and hence it took 2 days in all to complete the task. If A alone could complete the work in 2.625 days, how many days before the work getting over did A leave?

A and B can complete a task in 1.5 days. However, A had to leave a few days before the task was completed and hence it took 2 days in all to complete the task. If A alone could complete the work in 2.625 days, how many days before the work getting over did A leave? Correct Answer 0.875

⇒ A’s efficiency = 1/A = 1/2.625

⇒ (A + B)’s efficiency = (1/A) + (1/B) = (1/1.5)

⇒ (1/B) = (1/1.5) - (1/2.625) = 750/2625 = 10/35 = 2/7

Let A work for x days

⇒ Work done by A + Work done by B =1

⇒ (x/2.625) + {(2 × 2)/7} = 1

⇒ (8x/21) + (4/7) = 1

⇒ 8x/21 = 3/7

⇒ x = 9/8 = 1.125

⇒ A left the work for = 2 - x = 2 - 1.125 = 0.875

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