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X, Y, Z have some coins with them. Y has 40% more than what X has, and Z has 75% of the coins what X has. If X, Y, and Z together have 252 coins, then how many coins does X alone have?

X, Y, Z have some coins with them. Y has 40% more than what X has, and Z has 75% of the coins what X has. If X, Y, and Z together have 252 coins, then how many coins does X alone have? Correct Answer 80

GIVEN:

X, Y, Z have some coins with them. Y has 40% more than what X has, and Z has 75% of the coins what X has. X, Y, and Z together have 252 coins.

CONCEPT:

Basic percentage concept

FORMULA USED:
X as a percentage of Y = (X/Y) × 100

CALCULATION:

Suppose X has ‘x’ coins.

Number of coins with Y = 1.4x

And

Number of coins with Z = 0.75x

Total coins = 252

So,

x + 1.4x + 0.75x = 252

⇒ 3.15x = 252

⇒ x = 80

Hence, X has 80 coins.

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