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Two equal pots of milk and water are mixed together in the ratio 7 : 6. If the ratio of milk and water in the first pot was 4 : 1 and the ratio of milk and water in the second pot was 2 : 3 then find by how much percent the quantity of milk was more than the water in the final mixture?

Two equal pots of milk and water are mixed together in the ratio 7 : 6. If the ratio of milk and water in the first pot was 4 : 1 and the ratio of milk and water in the second pot was 2 : 3 then find by how much percent the quantity of milk was more than the water in the final mixture? Correct Answer 60%

Pot 1

Ratio of Milk and Water = 4 ∶ 1

∴ Quantity of Milk = 4/5

Quantity of Water = 1/5

Pot 2

Ratio of Milk and Water = 2 ∶ 3

∴ Quantity of Milk = 2/5

Quantity of Water = 3/5

Two equal pots are mixed in the ratio 7 ∶ 6

⇒ {(7 × 4/5) + (6 × 2/5)}/{(7 × 1/5) + (6 × 3/5)} = 40/25 = 8/5

∴ Ratio of Milk and water in the mixture is 8 ∶ 5

Required Percentage = {(8 - 5)/5} × 100 = 60%

∴ Quantity of milk in the mixture is greater than water by 60%

 

Related Questions

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Statements : Some pots are keys. Some keys are locks. All keys are rings.

Conclusions :
I. Some pots are locks.
II. Some pots are not locks.
III. Some pots are rings.
IV. Some pots are not rings.
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