Three businessmen hire a showroom for Rs. 25,200. If the first businessmen puts 20 electronic items for 8 days; the second businessmen puts 25 electronic items for 8 days; and the third businessmen puts 16 electronic items for 9 days; then what is the rent paid by each of them?

Three businessmen hire a showroom for Rs. 25,200. If the first businessmen puts 20 electronic items for 8 days; the second businessmen puts 25 electronic items for 8 days; and the third businessmen puts 16 electronic items for 9 days; then what is the rent paid by each of them? Correct Answer Rs. 8,000, Rs. 10,000, Rs. 7,200

Given:

Total cost of showroom = Rs. 25,200

Electronic items put by first businessman in 8 days = 20

Electronic items put by second businessman in 8 days = 25

Electronic items put by third businessman in 9 days = 16

Formula Used:

Total rent = Number of items × Number of days

Calculations:

Let the rent paid by first, second and third businessman be x, y and z respectively.

Rent paid by first businessman = 20 × 8

⇒ x = 160      ----(1)

Rent paid by second businessman = 25 × 8

⇒ y = 200      ----(2)

Rent paid by first businessman = 16 × 9

⇒ z = 144      ----(3)

From (1), (2) and (3), we get

x : y : z = 160 : 200 : 144

⇒ x : y : z = 20 : 25 : 18

Total cost of showroom = Rs. 25,200

Now, 1 unit = 25200/(20 + 25 + 18)

⇒ 1 unit = 400

⇒ x = 20 × 400 = Rs. 8,000

y = 25 × 400 = Rs. 10,000

z = 18× 400 = Rs. 7,200

∴ The rent paid by each businessman is Rs. 8,000, Rs. 10,000 and Rs. 7,200 respectively.