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Quantity I: Mc Donald farm has only Emus and Lions, the total count of legs was 14 less than 4 times the total count of heads. How many legs are counted in total? Quantity II: Mc Donald Farm has only Emus and Lions, the total count of legs was 15 less than 5 times the total count of the head. How many legs are counted in total?

Quantity I: Mc Donald farm has only Emus and Lions, the total count of legs was 14 less than 4 times the total count of heads. How many legs are counted in total? Quantity II: Mc Donald Farm has only Emus and Lions, the total count of legs was 15 less than 5 times the total count of the head. How many legs are counted in total? Correct Answer Quantity I = Quantity II or No Relation

Calculation:

Quantity I:

We know that Emus have 1 head and 2 legs.

We know that Lions have 1 head and 4 legs.

Let the number of Emus and Lions be x and y respectively.

According to the question:

⇒ (2x + 4y) + 14 = 4 (x + y)

⇒ 2x + 4y + 14 = 4x + 4y

⇒ 2x = 14

⇒ x = 7

∴ No of Emus is 7

Number of legs = (2x + 4y)

⇒ 14 + 4y

Quantity II:

We know that Emus have 1 head and 2 legs.

We know that Lions have 1 head and 4 legs.

Let the number of Emus and Lions be x and y respectively.

According to the question:

⇒ (2x + 4y) + 15 = 5 (x + y)

⇒ 2x + 4y + 15 = 5x + 5y

⇒3x + y = 15

Thus, we can not decide or calculate number of legs exactly.

No Relation can be established.

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