The high-frequency gain of the circuit shown in the figure is
The high-frequency gain of the circuit shown in the figure is Correct Answer Zero
Concept:
Capacitive reactance(XC) of a capacitor of capacitance(C) at a given frequency(f)
XC = 1 / (2πfC)
Inductive reactance(XL) of a inductor of inductance(L) at a given frequency(f)
XL = 2πfL
| XC | XL | |
|---|---|---|
|
At high frequencies (f → ∞) |
0 Ω (short-circuited) |
∞ Ω (open-circuited) |
|
At low frequencies (f → 0) |
∞ Ω (open-circuited) |
0 Ω (short-circuited) |
Calculation:
Given circuit is operating under a high-frequency operation then the capacitors get short-circuited.
Modified circuit after removing the redundant resistors is
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High frequency voltage gain = Vout / Vin = 0
