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A mixture of 200 liters of spirit and alcohol contains 40% alcohol. How much more alcohol should be added to the mixture to increase the percentage of alcohol to 50% in the new mixture?

A mixture of 200 liters of spirit and alcohol contains 40% alcohol. How much more alcohol should be added to the mixture to increase the percentage of alcohol to 50% in the new mixture? Correct Answer 40 liters

Given:

A mixture of 200 liters of spirit and alcohol contains 40% alcohol.

To increase the percentage of alcohol to 50%

Concept used:

Using allegation method

Calculation:

In 200 liters 40% alcohol

⇒ (40/100) × 200

⇒ 80 liters

And spirit

⇒ 200 – 80

⇒ 120

Using mixture and allegation

Ratio is 1 : 1

Let X liter of alcohol

Spirit is remain same so

⇒ (X/120) = 1

⇒ X = 120

Alcohol added

⇒ 240 – 200

⇒ 40 liters

∴ Alcohol should be added is 40 liters.

 

Alternate method:

In 200 liters 40% alcohol

So, alcohol is 80 liters and spirit is 120 liters   

In new mixture spirit is not change

So 50% of spirit = 120

And 50% of alcohol = 120

Total mixture is

⇒ 120 + 120

⇒ 240 liters

Alcohol added

⇒ 240 – 200

⇒ 40 liters

∴ Alcohol should be added is 40 liters.

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