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Four persons, P, Q, R, S were engaged for doing a task, with the condition that P; Q; R; S work, respectively, on (Mondays, Thursdays); (Tuesdays. Fridays); (Wednesdays, Saturdays); (Sundays). The task was began on a Monday, and got completed on the 15th day, which was also a Monday. If the efficiencies of P, Q, R, S in respect of doing this task were in the proportion 1 : 2 : 3 : 4, then in how many days could R complete the task, working alone without break?

Four persons, P, Q, R, S were engaged for doing a task, with the condition that P; Q; R; S work, respectively, on (Mondays, Thursdays); (Tuesdays. Fridays); (Wednesdays, Saturdays); (Sundays). The task was began on a Monday, and got completed on the 15th day, which was also a Monday. If the efficiencies of P, Q, R, S in respect of doing this task were in the proportion 1 : 2 : 3 : 4, then in how many days could R complete the task, working alone without break? Correct Answer 11

Given:

P; Q; R; S work, respectively, on (Mondays, Thursdays); (Tuesdays. Fridays); (Wednesdays, Saturdays); (Sundays)

Their efficiency ratio = 1 : 2 : 3 : 4

Calculation:

Work distribution from Monday to Sunday

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So, in 7 days total work = 16 units

So, in 14 days total work = 32 units

Now on Monday 1 unit more work will be done by P

So,

Total work = 33 units

Now, R will = 33/3 = 11 days to complete the task

∴ Required time to complete the task by R is 11 days

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