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A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A. The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a profit of 10%, then the highest possible cost of paint B, in Rs. per litre, is

A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A. The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a profit of 10%, then the highest possible cost of paint B, in Rs. per litre, is Correct Answer 20

Calculation:

Cost price of 10 litre solution = 264 × 100/110 = Rs.240

Cost price of one litre solution = 240/10 = Rs.24

Let cost price of B paint be Rs.a and cost price of A paint be Rs.(a + 8).

As per given condition, highest possible cost of B is when paints A and B are in equal ratio.

Using alligation rule,

⇒ 24 - a : (a + 8) - 24 = 1 : 1

⇒ 24 - a = a - 16

⇒ a = 20

∴ The highest possible cost of B is Rs.20

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