Which of the following statements are correct ? A. The sum of three consecutive multiples of 3 is 72. The largest number is 27. B. A number when multiplied by 13 is increased by 180. The number is 13. C. The average of first 20 multiples of 7 is 73.5. Choose the correct answer from the options given below:
Which of the following statements are correct ? A. The sum of three consecutive multiples of 3 is 72. The largest number is 27. B. A number when multiplied by 13 is increased by 180. The number is 13. C. The average of first 20 multiples of 7 is 73.5. Choose the correct answer from the options given below: Correct Answer <span style="">A and C only</span>
Given:A. The sum of three consecutive multiples of 3 is 72. The largest number is 27.
B. A number when multiplied by 13 is increased by 180. The number is 13.
C. The average of first 20 multiples of 7 is 73.5.
Formula used:
Average = ( First term + Last term ) / 2
Calculation:
Let the sum of three consecutive multiple of 3 is
( 3n ) + ( 3n + 3 ) + ( 3n + 6 ) = 72_____(i)
Largest no. = 27
( 3n + 6 ) = 27
3n = 27 - 6 = 21
n = 7
Put n=7 in (i)
( 3 ×7 ) + ( 3 × 7 + 3 ) + ( 3 × 7 + 6 ) = 21 + 24 + 27 = 72 (True)
Largest no. = 3 × 7 + 6 = 21 + 6 = 27 (True)
Now, the statement1 is true.
Statement2 says that a number when multiplied by 13 is increased by 180. The number is 13.
Let the no. = x
According To Question,
( 13 × x )= x + 180
13x - x = 180
12x = 180
x = 15
Now, the number is15.
But statement say the number is 13.
Now, the statement2 is wrong.
Statemen3 says that the average of first 20 multiples of 7 is 73.5.
The first 20 multiple of 7 is 7 + 14 + 21 + .......... 20terms
Here we find 20th term of multiple of 7
We know nth term of A.P is Tn = T1 + (n-1) × d
Tn is nth term of AP
n is no. of terms
d is common difference
Here, T1 = 7, d = 7, n = 20
T20 = 7 + ( 20 - 1 ) × 7
⇒7+19*7
⇒140
T20 = 140
Average = ( First term + Last term ) / 2
⇒( 7 + 140 ) / 2 = 73.5
Hence,Option3 is correct.