Which of the following statement are correct? A. The average of first twenty multiples of 8 is 84 B. There are 25 prime numbers between 100 to 200. C. Average of ten positive numbers is X. If each number is increased by 10%, then new average increases by 11%. Choose the correct answer from the options given below
Which of the following statement are correct? A. The average of first twenty multiples of 8 is 84 B. There are 25 prime numbers between 100 to 200. C. Average of ten positive numbers is X. If each number is increased by 10%, then new average increases by 11%. Choose the correct answer from the options given below Correct Answer A only
Calculation:
Statement A: The average of first twenty multiples of 8 is 84
First twenty multiples of 8 are:
⇒ 8 × 1, 8 × 2, 8 × 3,...........8 × 20
So, AP = 8 + 16 + 24, +..............+ 160
Required average = 8(1 + 2 + 3 + ............+ 20)/20
AP: Sum of first n numbers = n/2
Required average of AP = (8 + 160)/2 = 84
Hence, statement A is correct.
Statement B. There are 25 prime numbers between 100 to 200.
Prime numbers from 100 to 200 are:
101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 173, 179, 181, 191, 193, 197, 199.
There are 21 prime numbers between 100 to 200
Hence, statement B is incorrect.
Statement C. Average of ten positive numbers is X. If each number is increased by 10%, then new average increases by 11%.
Let the ten positive numbers be m1, m2, m3, ............ m10
Now, average of ten positive numbers is X.
⇒ X = (m1 + m2 + m3 +............+ m10)/10
If each number is increased by 10% then, new average Y is,
⇒ Y = (1.1m1 + 1.1m2 + 1.1m3 +............+ 1.1m10)/10
⇒ Y = 1.1 × (m1 + m2 + m3 +............+ m10)/10
⇒ Y = 1.1 × m
New average Y is increased by 10%
Hence, statement C is incorrect.
∴ Only statement A is correct.
Additional Information
- A prime number has exactly two factors and is a positive integer. If 'p' is a prime number, then 1 and p themselves are only necessary factors. Any number that does not obey this is called a composite number.