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There are 5 bags of rice of equal weight. The average weight of the bags is reduced by 34.8 kg, when 1/2, 1/3, 1/4, 1/5 and 1/6 part of the rice is removed from the respective bags. What is the average weight of the bags when 10 kg of rice is also taken out from the bags?

There are 5 bags of rice of equal weight. The average weight of the bags is reduced by 34.8 kg, when 1/2, 1/3, 1/4, 1/5 and 1/6 part of the rice is removed from the respective bags. What is the average weight of the bags when 10 kg of rice is also taken out from the bags? Correct Answer 83.2 kg

Let the weight of 1 rice bag be ‘x’ kg

Initial average weight of bags = 5x/5 = x kg

Quantity of rice removed from bags = x/2 + x/3 + x/4 + x/5 + x/6 = (29/20)x

As the average weight is reduced by 34.8 kg,

Quantity of rice removed from 5 bags = 34.8 × 5 = 174 kg

⇒ (29/20)x = 174

⇒ x = (174 × 20)/29 = 120 kg

Hence, new average = 120 - 34.8 = 85.2 kg

When 10 kg of rice is removed from 5 bags, the average is reduced by = 10/5 = 2 kg

∴ Required average = 85.2 - 2 = 83.2 kg

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