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The concentration of alcohol in same quantity of mixtures P and Q is 60% and 70% respectively and rest is water. When 10 litres of water added to each mixture then quantity of water in mixture P is 34 litres. When original quantity of mixtures P and Q are mixed, then find the difference between quantity of alcohol and quantity of water in their resultant mixture.

The concentration of alcohol in same quantity of mixtures P and Q is 60% and 70% respectively and rest is water. When 10 litres of water added to each mixture then quantity of water in mixture P is 34 litres. When original quantity of mixtures P and Q are mixed, then find the difference between quantity of alcohol and quantity of water in their resultant mixture. Correct Answer 36 litres

Given:

Let quantity of mixtures P and Mixture Q be m litres.

⇒ Quantity of water in mixture P after 10 litres addition = m × 40/100 + 10 = 34

⇒ m = 60 litres

⇒ Quantity of alcohol in resultant mixture = 60 × 60/100 + 60 × 70/100 = 78 litres

⇒ Quantity of water in resultant mixture = 120 - 78 = 42 litre

∴ Required difference = 78 - 42 = 36 litres

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