3 men, 5 women and 8 children are assigned to complete a work. If the efficiency of one woman is double than that of 1 child while efficiency of one man is double than that of one woman and one child alone can complete that work in 810 days. Calculate in how much time 3 men, 5 women and 8 children altogether will complete the whole work.
3 men, 5 women and 8 children are assigned to complete a work. If the efficiency of one woman is double than that of 1 child while efficiency of one man is double than that of one woman and one child alone can complete that work in 810 days. Calculate in how much time 3 men, 5 women and 8 children altogether will complete the whole work. Correct Answer 27
Efficiency ratio of 1 woman to 1 child = (2 : 1) × 2
Efficiency ratio of 1 man to 1 woman = 2 : 1
Efficiency ratio of 1 man, 1 woman and 1 child = 4 : 2 : 1
Total work = 1 × 810 = 810
Total efficiency of 3 men, 5 women and 8 children = (4 × 3 + 2 × 5 + 1 × 8) = (12 + 10 + 8) = 30
∴ 3 men, 5 women and 8 children altogether will complete the whole work in = 810/30 = 27
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Feb 20, 2025