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Find the common difference of an arithmetic progression whose 3rd term is 2 times the first term and 5th term is 99. 

Find the common difference of an arithmetic progression whose 3rd term is 2 times the first term and 5th term is 99.  Correct Answer 16.5

GIVEN:

3rd term is 2 times the first term and 5th term is 99.

FORMULA USED:

nth term of an arithmetic progression =

Where

a = first term, d = common difference, n = number of terms

CALCULATION:

Let first term be a and common difference be d

3rd term is 2 times the first term

⇒ = 2a

⇒ a = 2d     ---- (1)

5th term is 99

⇒ = 99

From equation 1:

= 99

⇒ d = 16.5

∴ common difference = 16.5

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