In an arithmetic progression (AP), the 9th term is 5 times the 2nd term and the 8th term is 1 more than 10 times the first term. What is the 4th term of the geometric progression (GP) whose first term is the second term of AP and whose common ratio is equal to the common difference of AP?

In an arithmetic progression (AP), the 9th term is 5 times the 2nd term and the 8th term is 1 more than 10 times the first term. What is the 4th term of the geometric progression (GP) whose first term is the second term of AP and whose common ratio is equal to the common difference of AP? Correct Answer 448

Given:

The 9th term is 5 times the 2nd term and the 8th term is 1 more than 10 times the first term. 

Formula used:

an = a + (n - 1)d

GP(geometric progression) nth term number 

Tn = ar(n - 1)

Where, a = first term, an = last term, d = common difference in AP, r = Common ratio in GP, Tn = n th term of GP 

Calculation:

The first term of AP is 'a' and common difference is 'd'

The 9th term is 5 times the 2nd term

⇒ 9th term = 5 times 2nd term

⇒ a + 8d = 5(a + d)

⇒ 3d = 4a

⇒ d = 4a/3      ----(1)

8th term is 1 more than 10 times the first term

⇒ a + 7d = 10 a + 1

⇒ 7d = 9a + 1     ----(2)

Putting the value of d in equation 2

⇒ 7(4a/3) = 9a + 1

⇒ a = 3

Putting value of 'a' in equation (1)

⇒ d = 4 × 3/3

⇒ d = 4

According to the question, 

Second term of AP = First time of GP 

⇒ 3 + 4 = 7

Common ratio of GP = 4

Tn = ar(n - 1)

⇒ T(4) = 7 × 4(4 - 1)

⇒ T(4) = 7 × 64 

⇒ 448

∴ The fourth term of GP is 448.

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