A student covers 25% of the distance to school on cycle, 20% of the distance on a bike, and rest in a rickshaw. While coming back he gets a lift from his father whose vehicle speed was 36 kmph and they reached home in 20 minutes. Calculate the distance covered by the boy in the rickshaw.

A student covers 25% of the distance to school on cycle, 20% of the distance on a bike, and rest in a rickshaw. While coming back he gets a lift from his father whose vehicle speed was 36 kmph and they reached home in 20 minutes. Calculate the distance covered by the boy in the rickshaw. Correct Answer 6600 m

Given:

Speed on vehicle = 36 kmph,

time = 20 minutes = 1200 seconds

Total distance = 25% cycle + 20% bike + 55% rickshaw

Formula used:

Speed = Distance / time

1 kmph = 5/18 m/s

Calculations:

Calculating total distance first

⇒ Distance = speed × time

⇒ D = 36 × 5 × 1200 / 18

⇒ D = 12000 m

Now,

⇒ Total distance D = 0.25D + 0.20D + 0.55D

⇒ Distance covered in rickshaw = 0.55 × 12000

⇒ Distance covered in rickshaw = 6600 m

∴ Distance covered in rickshaw by student is 6600 m