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Each of the questions below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. Ali is 3 years older than Bela who is 5 years older than Chals. The ratio of age of Dyna and Ena after two years will be 3 : 4 years. Sum of ages of Dyna, Ena, Fanny and Geet is 50 years. What is the present age of Geet? Statement I: The ratio of ages of Dyna and Fanny is 7 : 15 respectively and Ali is 18 years old. Statement II: The sum of ages of Ena and Fanny is 25 years. Statement III: The sum of ages of Dyna and Ena is 17 years and fanny is 8 years older than Dyna.

Each of the questions below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. Ali is 3 years older than Bela who is 5 years older than Chals. The ratio of age of Dyna and Ena after two years will be 3 : 4 years. Sum of ages of Dyna, Ena, Fanny and Geet is 50 years. What is the present age of Geet? Statement I: The ratio of ages of Dyna and Fanny is 7 : 15 respectively and Ali is 18 years old. Statement II: The sum of ages of Ena and Fanny is 25 years. Statement III: The sum of ages of Dyna and Ena is 17 years and fanny is 8 years older than Dyna. Correct Answer Either Statement III is sufficient alone or statement I and II together are sufficient.

Ali = 3 + Bela

Bela = 5 + Chales

(Dyna + 2) : (Ena + 2) = 3 : 4

Dyna = (3 Ena – 2)/4

Dyna + Ena + Fany + Geet = 50

7 Ena + 4 Fany + 4 Geet = 202

Statement I:

Ali = 18

Dyna : Fany = 7 : 15

Dyna = 7Fany/15

Dyna = (3Ena – 2)/4

Fany = (45Ena – 30)/28

Statement II:

Ena + Fany = 25

Statement III :

Dyna + Ena = 17

Dyna = (3Ena – 2)/4 = 17 – Ena

Ena = 10 years

Dyna = 17 – 10 = years

Fany = 8 + Dyna = 8 + 7 = 15 years

7Ena + 4Fany + 4Geet = 202

7 × 10 + 4 × 15 + 4A = 202

Geet = 18 years

From statement I and II :

Fany = (45Ena – 30)/28

Ena + Fany = 25

(45Ena – 30)/28 = 25 – Ena

Ena = 10years

Fany = 25 – 10 = 15 years

7Ena + 4Fany + 4Geet = 202

7 × 10 + 4 × 15 + 4A = 202

Geet = 18 years

Hence, either Statement III is sufficient alone or statement I and II together are sufficient.

Related Questions

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