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Three workers Ambika, Amba, and Ambalika complete a piece of work in 6 days. Ambika takes 15 days less than Amba to complete the same work. Find how many days will Ambalika complete the whole work alone with 75% of her efficiency, if Amba can alone complete the work in 35 days.

Three workers Ambika, Amba, and Ambalika complete a piece of work in 6 days. Ambika takes 15 days less than Amba to complete the same work. Find how many days will Ambalika complete the whole work alone with 75% of her efficiency, if Amba can alone complete the work in 35 days. Correct Answer 560/37

Given:

Ambika, Amba, and Ambalika complete a piece of work in = 6 days

Amba can alone complete the work in = 35 days

Ambika takes = 15 days less than Amba

Calculation:

Ambika + Amba + Ambalika = 6 days

Amba = 35 days

∴ Ambika = 35 - 15

⇒ 20 days

Let the total units of work be 420 units

∴ (Ambika + Amba + Ambalika)’s one day’s work = 70 units

∴ Ambika’s one day work = 21 units

∴ Amba = 12 units

∴ Ambalika’s one day work = 70 – 33

⇒ 37 units

Ambalika’s efficiency to do the work alone

⇒ 75/100 × 37

Time required to complete the work

⇒ (420 × 4)/(37 × 3)

⇒ 560/37 days

Ambalika completes the whole work alone with 75% of his efficiency in 560/37 days.

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