P and Q can complete whole work in 60/11 days and P can complete whole work alone in 12 days. If Q starts functioning only at 60% of its original capacity then in how many days will P and Q complete the whole work?
P and Q can complete whole work in 60/11 days and P can complete whole work alone in 12 days. If Q starts functioning only at 60% of its original capacity then in how many days will P and Q complete the whole work? Correct Answer (300/43) days
Given:
Time taken by P and Q both together = 60/11 days
Time taken by P alone = 12 days
Formula used:
Efficiency = (Total work)/(Time taken)
Calculation:
Total work = LCM of (60/11) and 12
⇒ 60 units
Efficiency of P and Q both together = {60/(60/11)}
⇒ 11 units
Efficiency of P = 60/12
⇒ 5 units
Now efficiency of Q = 11 - 5
⇒ 6 units
Time taken by Q = (60/6)
⇒ 10 days
If Q works at 60% of his efficiency,
Q's new efficiency = (60/100) × (6)
⇒ (18/5) units.
Hereafter, when P works with Q, their combined efficiency becomes,
⇒ 5 + (18/5)
⇒ (43/5) units
The total time taken by them together = {60/(43/5)}
⇒ (300/43) days
∴ P and Q complete the whole work in (300/43) days.