P and Q can complete whole work in 60/11 days and P can complete whole work alone in 12 days. If Q starts functioning only at 60% of its original capacity then in how many days will P and Q complete the whole work?

P and Q can complete whole work in 60/11 days and P can complete whole work alone in 12 days. If Q starts functioning only at 60% of its original capacity then in how many days will P and Q complete the whole work? Correct Answer (300/43) days

Given:

Time taken by P and Q both together = 60/11 days

Time taken by P alone = 12 days

Formula used:

Efficiency = (Total work)/(Time taken)

Calculation:

Total work = LCM of (60/11) and 12

⇒ 60 units

Efficiency of P and Q both together = {60/(60/11)} 

⇒ 11 units

Efficiency of P = 60/12

⇒ 5 units

Now efficiency of Q = 11 - 5

⇒ 6 units

Time taken by Q = (60/6)

⇒ 10 days

If Q works at 60% of his efficiency,

Q's new efficiency = (60/100) × (6)

⇒ (18/5) units.

Hereafter, when P works with Q, their combined efficiency becomes,

⇒ 5 + (18/5)

⇒ (43/5) units

The total time taken by them together = {60/(43/5)}

⇒ (300/43) days

∴ P and Q complete the whole work in (300/43) days.

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