Bissoy.com
Doctors Medicines MCQs Q&A

Related Questions

Which of the following are the correct statements with regard to positive skewed distribution? (A) Mean > Media > Mode (B) Mean < Median < Mode (C) Q3 - Median < Median - Q1 (D) Q3 - Median > Median - Q1 (E) Mean = Median = Mod Choose the correct answer from the options given below:
Which two of the following statements are true?  a) Skewness studies the flatness or peakedness of the distribution  b) A positively skewed distribution curve is stretched more to the right than to the left  c) On the basis of empirical relationship between mean, mode and median for moderately asymmetrical distribution, Karl Pearson's coefficient of skewness can be measured by 3 (Mean -Median) divided by Standard Deviation  d) If mean < mode, the distribution is positively skewed  Choose the correct option from those below: 
Consider the statements given below- A: Relationship between Mean, Median and Mode is : Mode = 3 Median – 2 Mean B: It is also possible that there can be more than one mode or no mode for a data set. C: In a data set, half of the data points are smaller than the median and half of the data points are larger. Which of the above statement(s) is/are TRUE?
If Mean is M, Median is Md, Mode is Mo, what is the relation between Mean, Median and Mode? 
The maximum weight lifted by 750 participants are recorded and it is found that the Mean and the Median of this distribution are both more than the Mode. If the Mean and the Median are 184 Kg and 178 Kg respectively, then which of the following is the most likely value of the Mode (in kg).
Given below are two statements: Statement I: In a classroom assessment, a teacher finds that the distribution of students' score is positively skewed. Hence, the mean of scores will be greater than median and median will be greater than mode. Statement II: When the distribution of students' score is found to be normal, all the three measures of central tendency coincide. In the light of the above statements, choose the most appropriate answer from the options given below:
Given for an asymmetrical distribution, median=20, mean=22, what is the mode?
Statement I Exponential probability distribution has the mean = $$\frac{1}{\mu }$$ and variance = $$\frac{1}{{{\mu ^2}}}$$
Statement II The mean, median and mode do not coincide in the normal distribution.
Statement III The binomial distribution is symmetrical for any value of p (probability of success).
hat will be the output of the following R code?
> centre <- function(x, type) {+ switch(type,+ mean = mean(x),+ median = median(x),+ trimmed = mean(x, trim = .1))+ }> x <- rcauchy(10)> centre(x, "mean")
What is the formula for the median of Grouped data? * h b) Median = L + * h c) Median = L + + h d) Median = L * * h