A shaft rotating N.R.M. under a torque T, transmits a power
A
$$\frac{{{\text{T}}\pi {\text{N}}}}{{30}}$$ Newton metres/sec
B
$$\frac{{{\text{T}}\pi {\text{N}}}}{{30}}$$ Newton metres/min
C
$$\frac{{{\text{T}}\pi {\text{N}}}}{{60}}$$ Newton metres/min
D
$$\frac{{{\text{T}}\pi {\text{N}}}}{{60}}$$ Newton metres/sec
Correct Answer: $$\frac{{{\text{T}}\pi {\text{N}}}}{{30}}$$ Newton metres/sec