Determine power rating of an electric motor if it runs at 1440 rpm and line shaft transmits torque of 75 Nm. Assume Reduction ratio =1.6

A 10.36 kW
B 11.3 kW
C 7.068kW
D 9.12kW

Correct Answer: 7.068kW

i = n / N 1.6 = 1440 / N N = 900 r.p.m P = (2 π x 1440 x 75) / 60 = 7068 W = 7.068 kW The power rating of an electric motor is 7.068 kW
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