Related Questions

The range of projectile on a downward inclined plane is ________ the range on upward inclined plane for the same velocity of projection and angle of projection.
A Less than
B More than
C Equal to
D None of these
For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is
A $$\alpha = \frac{\pi }{4} - \frac{\beta }{2}$$
B $$\alpha = \frac{\pi }{2} + \frac{\beta }{2}$$
C $$\alpha = \frac{\beta }{2} - \frac{\pi }{2}$$
D $$\alpha = \frac{\pi }{4} - \frac{\beta }{4}$$
E $$\alpha = \frac{\pi }{2} - \frac{\beta }{2}$$
The Cartesian equation of trajectory is (where u = Velocity of projection, $$\alpha $$ = Angle of projection and x, y = Co-ordinates of any point on the trajectory after t seconds.)
A $${\text{y}} = \frac{{{\text{g}}{{\text{x}}^2}}}{{2{{\text{u}}^2}{{\cos }^2}\alpha }} + {\text{x}}\tan \alpha $$
B $${\text{y}} = \frac{{{\text{g}}{{\text{x}}^2}}}{{2{{\text{u}}^2}{{\cos }^2}\alpha }} - {\text{x}}\tan \alpha $$
C $${\text{y}} = {\text{x}}\tan \alpha - \frac{{{\text{g}}{{\text{x}}^2}}}{{2{{\text{u}}^2}{{\cos }^2}\alpha }}$$
D $${\text{y}} = {\text{x}}\tan \alpha + \frac{{{\text{g}}{{\text{x}}^2}}}{{2{{\text{u}}^2}{{\cos }^2}\alpha }}$$
The angle of projection for a range is equal to the distance through which the particle would have fallen in order to acquire a velocity equal to the velocity of projection, will be
A [[[
Angles project true size only when the plane containing the angle and plane of projection are this:
A Adjacent
B Aligned
C Perpendicular
D Parallel
If the direction of projection bisects the angle between the vertical and the inclined plane, then the range of projectile on the inclined plane is
A Zero
B Maximum
C Minimum
D None of these
The direction of projection should bisect the angle between the inclined plane and the vertical for a range of a projectile on inclined plane
A To be zero
B To be maximum
C To be minimum
D None of these
A body of weight 'W' is required to move up on rough inclined plane whose angle of inclination with the horizontal is 'α'. The effort applied parallel to the plane is given by (where μ = tanφ = Coefficient of friction between the plane and the body.)
A P = W tanα
B P = W tan (α + φ)
C P = W (sinα + μcosα)
D P = W (cosα + μsinα)
Plane P take off at 2:00 am and flies at a constants speed of Xmph. Plane Q takes off at 3:30 am and flies the same forte as plane p but travels at a constant X, how many hours after 3:30 am will plane Q overtake plan P?
A 1.5x/y +0.5
B 2
C 4
D 5
This type of auxiliary view is projected onto a plane that is perpendicular to one of the principal planes of projection:
A Primary
B Secondary
C Revolved
D Successive

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