The torque transmitted by a solid shaft of diameter (D) is (where $$\tau $$ = Maximum allowable shear stress)
A
$$\frac{\pi }{4} \times \tau \times {{\text{D}}^3}$$
B
$$\frac{\pi }{{16}} \times \tau \times {{\text{D}}^3}$$
C
$$\frac{\pi }{{32}} \times \tau \times {{\text{D}}^3}$$
D
$$\frac{\pi }{{64}} \times \tau \times {{\text{D}}^3}$$
Correct Answer: $$\frac{\pi }{{16}} \times \tau \times {{\text{D}}^3}$$